Question

How many terms are there in G.P 0.03 , 0.06 , 0.12 ........... 3.84 .

Answer 1

Hey mate :
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Here is yr answer.......


Given G. P. ,

0.03 , 0.06 , 0.12 , ...........3.84

[a1 (a) - first term]

[r - common ratio]

[ n - no. of terms]

a1 = 0.03

r = 2

[ a × r^(n-1) ] - use the identity...


3.84 = 0.03 × 2^(n-1)

3.84/0.03 = 2^(n-1)

128 = 2^(n-1)

2^7 = 2^(n-1)


Here, bases are equal... so, their powers must be equal!!

So,

7 = n-1

n = 7+1

n = 8


Therefore, no. of terms = 8


Hope it helps...

# brainly..

Answer 2

Let 0.03 be the first term and 3.84 be the last term.




First term = a = 0.03


Second term = ar = 0.06


Common Ration = r =
0.06 / 0.03 = 0.12 / 0.06 = 2


Last term = l = 3.84



From the formulas of GP,



nth term = $ar^{n-1}$


lth term = $ar^{l-1}$


3.84 = 0.02 × $(2)^{l-1}$


128 = $2^{l - 1}$


2^{7} = 2^{ l - 1 }

8 = l



Therefore 3.84 is 8th term of the GP