Math, asked by sharanyakonar4, 8 months ago

How many terms are there in the AP 41,38, 35, ..., 8?​

Answers

Answered by shahrukhasif307
0

Answer:

a + (n-1)d= nth term

Step-by-step explanation:

a=41

nth term = 8

d= -3

Answered by Anonymous
10

Given :

  • An AP 41, 38, 35.......8.

To Find :

  • Number of terms.

Solution :

Here

  • 1st term = T1 (a) = 41
  • 2nd term = T2 = 38
  • Common difference = d = 38 - 41 = -3

As we know that

  • Tn = a + (n - 1)d

Now

According to question :

→ 8 = a + (n - 1)d

→ 8 = 41 + (n - 1)(-3)

→ 8 = 41 + (-3n) + 3

→ 8 = 44 - 3n

→ 44 - 8 = 3n

→ 3n = 36

→ n = 36/3

→ n = 12

Hence,

  • The number of terms in the AP is 12.

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