Question

how many terms are there in the expansion of (1+2x x^2) ^5 + (1 + 4y + 4y^2) ^5.​

Answer 1

hence total number of terms are 21

Answer 2

Answer:

21 terms are there in the given expansion

Step by step explanation:-

As we know that total no. of terms in (a+b)

n is (n+1).

(1+2x+x^2 )^5 +(1+4y+4y^2 )^5

=((1+x)^2 )^5+((1+2y)^2)^5

=(1+x)^10 +(1+2y)^10

Therefore,

Total no. of terms =(10+1)+(10+1)−1=11+11−1=21