how many terms are there in the following:1)-1,-5/6,-2/3,...,10/3.
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In the given series,
a=-1,d=-5/6-(-1)=-5/6+1=(-5+6)/6=1/6,l=10/3
l=a+(n-1)d
10/3=(-1)+(n-1)1/6
10/3=-1+n/6-1/6
10/3=(-6+n-1)/6
10/3=(n-7)/6
(10/3)*6=(n-7)
10*2=n-7
20=n-7
n=20+7
n=27...
Therefore,the number of terms in the given series is 27.
a=-1,d=-5/6-(-1)=-5/6+1=(-5+6)/6=1/6,l=10/3
l=a+(n-1)d
10/3=(-1)+(n-1)1/6
10/3=-1+n/6-1/6
10/3=(-6+n-1)/6
10/3=(n-7)/6
(10/3)*6=(n-7)
10*2=n-7
20=n-7
n=20+7
n=27...
Therefore,the number of terms in the given series is 27.
lohithanaidu:
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In the given series or A.P............... a= -1....... d= -5/6-(-1)=-5/6+1=-5+6/6=1/6 ......... nth term = 10/3............ Now, an= a+(n-1)d...... 10/3= -1+(n-1)1/6.........10/3+1=(n-1)1/6........... 10+3/3=(n-1)1/6...........13/3×6/1= n-1.......78/3=n-1.............. 78/3+1= n.......78+3/3=n. ......... 81/3=n.....27=n....... Therefore there are 27 terms in the series or A.P.
Actually last time I didn't saw 1 of nth term and took it 0/3.... Sry ... My bad !! ... .... Hey if u don't mind then plzz mark it as best...
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