Question

how many terms are there in the GP 0.03,0.06,0.12,...........,3.84

Answer 1

Given,

a=0.03

Last term =3.84

d=2

Last term =0.03×2^(n-1)

3.84=0.03×2^(n-1)

128=2^n-1

2^7=2^n-1

n=8,,

The term is 8,,,,

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Answer 2

Answer:

Step-by-step explanation

a = 0.03, r = 0.06/0.03= 2

In GP, we have to find 'n'

n th term= a r^( n-1) =3.84

0.03(2) ^n-1 = 3.84

2^(n-1) = 3.84/0.03= 128

2^n = 128 x2= 256 =2^8

n = 8