Question

How many terms are there in the odd numbers 1, 3, 5,

…,99,101?​

Answer 1

 

Sn=2n[2a+(n−1)d]

S101=2×101[2×1+(101−1)2]

S101=202[(200)22]

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Answer 2

Answer:

51

Step-by-step explanation:

$a_{1} \: = 1$

$a_{2} \: = 3$

d= 3-1

= 2

l = 101

according to question

$t_{n} \: = \: a + (n - 1)d$

101 = 1 + (n-1) 2

101-1 = 2n -2

100 = 2n-2

2n = 100+2

n = 102 / 2

n = 51