Question

how many terms are there in the sequence 3,6,9,12.....111?​

Answer 1

there only are totally 37

Answer 2

given series is in A.P

1st term(a)=3

last term=111

common difference =3

let no of terms be 'n'

nth term=a+(n-1)d

111=3+(n-1)×3

111=3n

n=37