how many terms are there in the sequence 60,56,52,.......,-56.
Answers
Answered by
1
-56=60+(n-1)(-4)
-116/-4=n-1
29=n-1
n= 30 ...hope so it helps
-116/-4=n-1
29=n-1
n= 30 ...hope so it helps
Answered by
1
in the AP: 60, 56, 52, ......., -56
a = 60
d = -4
an= -56
an = a+(n-1) d
-56 = 60 + (n-1) (-4)
-56-60 = (-4)(n-1)
-116/-4 = (n-1)
29= n-1
n = 29+1
n= 30
there are 30 terms.
a = 60
d = -4
an= -56
an = a+(n-1) d
-56 = 60 + (n-1) (-4)
-56-60 = (-4)(n-1)
-116/-4 = (n-1)
29= n-1
n = 29+1
n= 30
there are 30 terms.
Similar questions