Question

how many terms are there in the sequence of 2,5,8,11,....104​

Answer 1

Hi !

solution :-

Given , a = 2,

d = 5-2=3

Tn = 104

formula from nth term of an A.P

tn = a + (n -1)d

104 = 2 + (n-1)×3

104 = 2 + 3n-3

3n = 105

n = 105/3 = 35 term in this sequence of Ap .

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Hope it's helpful

Answer 2

Answer:

No. Of terms is 35

Step-by-step explanation:

a= 2

d=3

an- 104

an = a +(n-1)d

104 = 2 + (n-1) 3

104-2 = (n-1) 3

102/3= (n-1)

34+1 = n

N= 35