Question

how many terms are there in the series 4,7,10,13,......148

Answer 1

a + (n-1)d = last term
4 + (n-1)3 = 148
      (n-1)3 = 148 - 4
      (n-1)   = 144/3
       n       = 48 + 1
       n       = 49

Answer 2

Answer:

Step-by-step explanation:

ACCORDING TO THE QUESTION

a=4---first term

d=3---common difference

tn=148---last term

n= ?---no.of terms on the series

using formula

⇒a + (n-1)d = tn

⇒∴4 + (n-1)3=148

⇒∴(n-1)3=148 - 4

⇒∴(n-1)=144/3

⇒∴n=48 + 1

⇒∴n=49

n=no.of terms in the sequence=49

∴There are 49 terms in the given series

HOPE IT HELPS YOU