Question

How many terms in AP 7,13,19,………… 199?

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Answer 1

Answer:

Here,

a = 7

d = 6

an = 199

wkt,

an = a + (n-1)d

substituting the values, we have:

$199 \: = \: 7 + \: ( n - 1) \: 6 \\ \\ 199 = 7 + 6n - 6 \\ \\ 199 = 1 + 6n \\ \\ 199 - 1 = 6n \\ \\ 198 = 6n \\ \\ \frac{198}{6} = n \\ \\ n = 33$

Therefore there are 33 terms in this AP.

Answer 2

Answer:

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