Question

How many terms lf g.P.3,3/2,3/4...Are needed to give the sum 3069/512?

Answer 1

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Answer 2

Answer:

10

Step-by-step explanation:

GP : .3,3/2,3/4....

First term = 3

Common ratio = r = $\frac{\frac{3}{2}}{3}=\frac{\frac{3}{4}}{\frac{3}{2}}=\frac{1}{2}$

Sum of n terms formula : $\frac{a(r^n -1}{r-1}$

We are supposed to find How many terms are needed to give the sum 3069/512

So, $\frac{3069}{512}=\frac{3((\frac{1}{2})^n -1}{\frac{1}{2}-1}$

[tex]n = 10/tex]

SO, 10 terms needed to give the sum 3069/512