How many terms of A.P 2,7,12,17add upto 990.
Answers
Answered by
4
Answer:
Let a be the first term and d be the common difference.
Given series is 2,7,12,17... 990.
Here,
= > a = 2, n = 990
d = 7-2 = 5.
We know that sum of n terms of an AP sn = (n/ 2)[2a + (n - 1) * d]
= > (990/2)[2(2) + (990 - 1) * 5]
= > 495[4 + (989) * 5]
= > 495[4949]
= > 2449755.
Hope this helps!
Step-by-step explanation:
pls mark brainliest
Answered by
1
Step-by-step explanation:
hope it is helpful to you and mark me as a brainlist friend
Attachments:
Similar questions