how many terms of an ap 1,9,17,25 must be given a sum of 644
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Answer:
a=1
d=9-1=8
Sn=644
n=?
Sn=n/2[2a+(n-1)d]
644=n/2[2*1+(n-1)8]
644*2=n(2+8n-8)
1288=2n+8n²-8n
1288=8n²-6n
8n²-6n-1288=0
or 4n²-3n-644=0///////now i can not solve
further you can solve
Step-by-step explanation:
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