How many terms of an AP 65,60,55,... be taken,so that their sum is 0 ?
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Answered by
194
Heya !!!
AP = 65 , 60 , 55
Here,
First term (A ) = 65
Common Difference (D) = 60-65 = -5
Sn = 0
N/2 × [ 2A + ( N-1) × D ] = 0
N × [ 2 × 65 + ( N-1) × -5 ] = 0 × 2
N ( 130 -5N + 5 ) = 0
130 - 5N + 5 = 0/N
135 - 5N = 0
-5N = -135
N = -135/-5
N = 27
Hence,
27 terms must be added to get the sum 0.
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
AP = 65 , 60 , 55
Here,
First term (A ) = 65
Common Difference (D) = 60-65 = -5
Sn = 0
N/2 × [ 2A + ( N-1) × D ] = 0
N × [ 2 × 65 + ( N-1) × -5 ] = 0 × 2
N ( 130 -5N + 5 ) = 0
130 - 5N + 5 = 0/N
135 - 5N = 0
-5N = -135
N = -135/-5
N = 27
Hence,
27 terms must be added to get the sum 0.
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
Anonymous:
Perfect !!
Answered by
75
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Thanks
Have a good day
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