Question

How many terms of an AP:9,17,25.......must be taken to give a sum of 636​

Answer 1

Answer:

Please refer to the attachment

Step-by-step explanation:

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Answer 2

Answer:

a = 9

d = 17-9 = 8

Sn = 636

n = ?

Sn = n/2 [2a+(n-1)d]

636 = n/2 [2×9+(n-1)8]

1272 = n[10+8n]

8n²+10n-1272 = 0

4n²+5n-636=0

Now...by factorisation or any other relevant method, u can find the answer....