Question

how many terms of an ap 9 17 25 must be taken to give a sum of 636​

Answer 1

Answer:

Here,

a

1

=9

a

2

=a

1

+d=17

9+d=17

d=8

We know that, the sum of n terms of an A.P. is,

S

n

=

2

n

{2a+(n−1)d}

According to the question,

636=

2

n

{2(9)+(n−1)8}

1272=18n+8n

2

−8n

8n

2

+10n−1272=0

4n

2

+5n−636=0

n=12,−13.25

Ignore the negative value.

n=12

Hence, 12 terms of the A.P. is required to give a sum of 636.

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Answer 2

Answer:

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