how many terms of ap -10,-8 must be taken to get the sum of 26
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Step-by-step explanation:
a=-10
d=2
n=?
We know that
n*(2a+(n-1)d)//2=26
n*(-20+2n-2)//2=26
-22n+2n²=52
2n²-22n-52=0
n²-11n-26=0
n²-13n+2n-26=0
n(n-13)+2(n-13)
n=-2//n=13
n=13
Hope it helps
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