How many terms of Ap 18 , 16, 14 be taken so their sum is zero
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Hey dear friend
A.P.=18,16,14,.,.,
where
a=18. d= -2. Sn=0
To find-:
no. of terms so their sum is 0.
By the formula
=>Sn=n/2[2a+(n-1)d]
=>0=n/2[2*18+(n-1)(-2)]
=>0=n/2[36-2n+2]
=>0=n/2[38-2n]
=>0=19n-n²
=>n²=19n
=>n²/n=19
=>n=19
So, the no. of terms should be taken so their sum is 0 = 19terms
Be PERFECTIONIST
hope it helps you mark me as brainliest and
A.P.=18,16,14,.,.,
where
a=18. d= -2. Sn=0
To find-:
no. of terms so their sum is 0.
By the formula
=>Sn=n/2[2a+(n-1)d]
=>0=n/2[2*18+(n-1)(-2)]
=>0=n/2[36-2n+2]
=>0=n/2[38-2n]
=>0=19n-n²
=>n²=19n
=>n²/n=19
=>n=19
So, the no. of terms should be taken so their sum is 0 = 19terms
Be PERFECTIONIST
hope it helps you mark me as brainliest and
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