how many terms of ap 22,10,18.... should be taken so their sum is zero
Answers
Answered by
2
***AS PER YOUR QUESTION THEIR IS NO SOLUTION
if A. P
22, 20, 18,...
(first term) a = 22
(common difference) d = 20 - 22 = - 2
(sum of terms) Sn = 0
FORMULA
Sn = n [a + (n - 1)d] / 2
SUBSITUTE
0 = n [22 + (n - 1) (- 2)] / 2
Cross multiply
0 = n [22 + (n - 1) (- 2)]
open small bracket
0 = n [22 - 2n + 2]
open large bracket
0 = 24n - 2n^2
Divide by n as it is common
0 = 24 - 2n
2n = 24
n = 24 / 2
n = 12
Therefore. Number of terms is 12 whose sum is zero.
if A. P
22, 20, 18,...
(first term) a = 22
(common difference) d = 20 - 22 = - 2
(sum of terms) Sn = 0
FORMULA
Sn = n [a + (n - 1)d] / 2
SUBSITUTE
0 = n [22 + (n - 1) (- 2)] / 2
Cross multiply
0 = n [22 + (n - 1) (- 2)]
open small bracket
0 = n [22 - 2n + 2]
open large bracket
0 = 24n - 2n^2
Divide by n as it is common
0 = 24 - 2n
2n = 24
n = 24 / 2
n = 12
Therefore. Number of terms is 12 whose sum is zero.
Answered by
0
Answer:
Step-by-step explanation:
Attachments:
Similar questions