how many terms of AP 27,24,21...should be taken so that their sum is 0
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0
Answer:
9th term
Step-by-step explanation:
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Answered by
1
Answer:
19 terms
Step-by-step explanation:
AP: 27,24,21......
a = 27
d = -3
Sn = n/2[2a + (n-1)d] = 0
n/2(54+3-3n)= 0
n(57-3n) = 2×0
57n - 3n^2 = 0
3n^2=57n
3n=57. (n gets cancelled)
n=19
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