how many terms of geometric series 1 + 4 + 16 + 64 + will make the sum 5461 ?
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Answer:
Sum (Sn) = a*(rn -1)/(r-1)
5461 = 1 *(4n -1)/3
4n = 16383 +1
4n = 16384
4n = 4 7
So, n = 7
No of terms = 7
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