Question

How many terms of the
a.p. 22, 20, 18 should be taken so that their sum is zero?

Answer 1

hope it will help uou.

Answer 2

There are 23 terms in the AP so that their sum is equal to 0.

Step-by-step explanation:

The AP is 22, 20, 18.....

We need to find the number of terms in the AP so that their sum is equal to 0. The sum of n terms of an AP is given by :

$S=\dfrac{n}{2}[2a+(n-1)d]$

a is first term, a = 22

d = 20-22 = -2

S = 0

So,

$0=\dfrac{n}{2}[2(22)+(n-1)(-2)]\\\\0=\dfrac{n}{2}[46-2n]\\\\n(23-n)=0\\\\n=23$

So, there are 23 terms in the AP so that their sum is equal to 0.

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