how many terms of the A.P. 22,20,18..... should be taken so that their sum is zero
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Answer:
let a=22
d=-2
22+(n-1)-2=0
22-2n+2=0
-2n=-24
n=12
12/2(2*22+(12-1)*-2) =0
6(44-22)
6*22
=132
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