How many terms of the A.P. 7, 11, 15, 19_____ must be taken to get the sum 297?
Answers
Answered by
0
Answer:
Let the number of terms be 'n'
n/2(2×7(n-1)4)=297
n(7+2n-2)=297
2n^2+5n-297=0
2n^2+27n-22n-297=0
n(2n-27)-11(2n-27)=0
(n-11)(2n-27)=0
n=11 or n=27/2
Required number of terms=11
If you like answer, please mark it as brainliest.
I hope you will love this answer.
If you have any doubts,ask me.
Follow and thank me.
Your friend-
Sahil kumar
Similar questions
Environmental Sciences,
4 months ago
Math,
4 months ago
Science,
4 months ago
English,
9 months ago
Math,
9 months ago