Question

How many terms of the A.P. 7, 11, 15, 19_____ must be taken to get the sum 297?

Answer 1

Answer:

Let the number of terms be 'n'

n/2(2×7(n-1)4)=297

n(7+2n-2)=297

2n^2+5n-297=0

2n^2+27n-22n-297=0

n(2n-27)-11(2n-27)=0

(n-11)(2n-27)=0

n=11 or n=27/2

Required number of terms=11

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