how many terms of the ap -15, -13, -11..... needed to make the sum +55
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5
Step-by-step explanation:
55=n/2(2a+n-1)d
110=n(2*-15+(n-1)*2)
110=n(-30+2n-2)
110=-32n+2n^2
55=-16n+n^2
n^2-16n-55=o
after doing factor
n-5=0
n=5
or
n-11=0
n=11
thanks
hope its helpful.....
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