How many terms of the ap 20 19 18 should be taken so that their sum is 300?
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Answer:
Given : a =20
d=-1
Sn=300
Too find : n=?
Step-by-step explanation:
Sn = n/2[2a+(n-1)d]
300 = n/2[2*20+(n-1)(-1)]
300*2/n=40-n+1
600/n =41-n
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