how many terms of the AP 27,24,21............... should be taken so that there sum is zero
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Step-by-step explanation:
0=n/2[2(27)+(n-1)-3]
0=n/2[54+3-3n]
0=n/2[57-3n]
0=3n/2[19-n]
n=19
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Hope it helps
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