Math, asked by mrigankisingh123456, 8 months ago

How many terms of the ap:3,9,15,21,..........must be taken to given sum of 1875

Answers

Answered by Asterinn
1

Answer:

No. Of terms= 25

Step-by-step explanation:

n/2(2a + (n-1)d) = sum of ap

n/2(6 + (n-1)6) = 1875

n(6 + (n-1)6) = 3750

6n +6n² - 6n = 3750

n +n² - n = 625

n²= (25)²

n = 25

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