how many terms of the AP 52,48,44.. must be taken so that the sum may be 360?
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AP: 52,48,44.......
Here,
a = 52
d = -4
To find Sn = 360
Sn = n\2 (2a+(n-1)d)
2*360=n(2*52+(n-1)-4)
720 = n(104-4n+4)
720 = 104n -4n²+4n
4n²-108n+720 = 0
n²-27n+180 = 0
Sum of 15 terms or 12 terms of this AP is 360.
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hello7777:
it is possible
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