how many terms of the AP 7,11,15 etc be taken to get the sum 250 ( with steps)
Answers
Answer:
10
Step-by-step explanation:
7,11,15.... are in A.P.
a=7 d=11-7=4 Sn=250 n=?
Sn=n/2(2a+(n-1)d)
500=n(14+4n-4)
500=14n+4n^2-4n
4n^2+10n-500=0
n=− 25 /2 or 10
as n cannot be negative
n=10
Given :-
Arithmetic progession ;
7 , 11 , 15 . . . . . . . .
Required to find :-
- Sum of how many terms of the AP is 250
Formula used :-
Solution :-
Given information :-
AP = 7 , 11 , 15 . . . . . . . .
we need to find the sum of how many terms of the AP is 250
Consider the given information
AP = 7 , 11 , 15 . . . . .
- First term ( a ) = 7
Common difference = ( 2nd term - 1st term ) = ( 3rd term - 2nd term )
=> ( 7 - 11 ) = ( 15 - 11 )
=> ( 4 ) = ( 4 )
- Common difference ( d ) = 4
Using the formula ;
Here,
- a = first term
- d = common difference
- n = the term number till which you want to find the sum
- Number of terms = 60
Therefore ,
Sum of first 60 terms of the AP is 250
Additional Information :-
Formula to find the nth term of the arithmetic progession is ;
The simplified formula to find the sum of the nth term ( when last term is given ) is ;
Note :-
This formula is used reduce the calculations . In order to use this formula you need to know the last term till which you want to find the sum .