Math, asked by chanchiyaveena, 5 months ago

How many terms of the AP 78, 71, 64 ... are needed to give the sum 468? Also find the last term of this AP.

Answers

Answered by Anonymous
13

Answer:

a=78

d= -7

an= 468

an = a+(n-1)d

468 = 78+(n-1)(-7)

468= 78+ (-7n) +7

468-85 = 7n

(468 - 85) \div 7 = n

383/7 = n

n=55

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8

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