how many terms of the AP 8,15,22,... add upto 1490?
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A.P=8,15,22,...,1490.
means, First term(a)=8.
common difference (d)=15-8=22-15=7.
nth term of A.P=1490.
Since we know that ,
nth term= a+(n-1)d.
1490=8+(n-1)7
1490-8=(n-1)7
1482/7=n-1
n-1=1482/7
n=1482/7+1
which is not possible because value of ,,n,,,,,
is always natural number.
Thanks B brainly always...
means, First term(a)=8.
common difference (d)=15-8=22-15=7.
nth term of A.P=1490.
Since we know that ,
nth term= a+(n-1)d.
1490=8+(n-1)7
1490-8=(n-1)7
1482/7=n-1
n-1=1482/7
n=1482/7+1
which is not possible because value of ,,n,,,,,
is always natural number.
Thanks B brainly always...
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