Math, asked by neelshaileshphktnu, 1 year ago

how many terms of the AP 8,15,22,... add upto 1490?

Answers

Answered by nitishray57
4
A.P=8,15,22,...,1490.

means, First term(a)=8.

common difference (d)=15-8=22-15=7.

nth term of A.P=1490.

Since we know that ,

nth term= a+(n-1)d.

1490=8+(n-1)7

1490-8=(n-1)7

1482/7=n-1

n-1=1482/7

n=1482/7+1

which is not possible because value of ,,n,,,,,

is always natural number.

Thanks B brainly always...
Similar questions