. How many terms of the AP 9, 17, 25, ... must be taken so that their sum
is 6362
(CBSE 2017]
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4
hey buddy.......
thanks for the question.....
AP is 9, 17, 25, .........
d=17-9=8
n=?
Sn=n/2[2a+(n-1)d]
6362= n/2[2×9+(n-1)8]
6362=n/2[18+8n-8]
6362=n×5+8n
6362=13n
n=489.38
hope it helps mark me as brainliest...
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:)
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