how many terms of the AP: 9,17,25,.......... must be taken so that their sum is 636 in the form of factorization
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Number of terms of the AP [ 9 , 17 , 25 ] which are required to make the sum of 636 is 12
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Answer: Sn=636
A=9
D=8
Sn=n/2{2a+(n-1)d}
636=n/2{2×9+(n-1)8}
636×8=n{9+(n-1)
=n{
Step-by-step explanation:
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