how many terms of the ap : 9, 17 ,25,........ must be taken to give a sum of 636?
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Answered by
16
Now solve for n... And get your answer
Answered by
27
a=9
d=8
Sn=636
Sn=n/2[2a+(n-1)d]
636=n/2[2×9+(n-1)8
636=n/2[18+8n-8]
636=n/2[10+8n]
636=5n+4n^
4n^+5n-636=0
Then by quadratic formula solve this equation and get n.
d=8
Sn=636
Sn=n/2[2a+(n-1)d]
636=n/2[2×9+(n-1)8
636=n/2[18+8n-8]
636=n/2[10+8n]
636=5n+4n^
4n^+5n-636=0
Then by quadratic formula solve this equation and get n.
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