How many terms of the Arithmetic Progressions 3,7,11,.........are needed for the sum to give the sum 300? Also find the last term of the AP?
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Answered by
13
sn= n/2(2a+(n-1)d)
300 = n/2 (6+ (n-1)4)
300 = n/2 (6+4n-4)
600= n( 2+4n)
600 = 2n + 4n 2
4n 2 +2n -600
plzzzz solve this after this
u can solve this by splitting the middle term...
300 = n/2 (6+ (n-1)4)
300 = n/2 (6+4n-4)
600= n( 2+4n)
600 = 2n + 4n 2
4n 2 +2n -600
plzzzz solve this after this
u can solve this by splitting the middle term...
riyaz15:
txs
Answered by
6
this is your required answer.☺️
Attachments:
x2+2√2x-6
this is your answer. x^2+3√2x-√2x-6=0. take common and solve further.
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