How many terms of the arithmetic sequence 2 8 14 20 will give a sum of 660
Answers
Answer:
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First 15 terms of the arithmetic sequence 2 8 14 20 will give a sum of 660
Solution:
Given is a arithmetic progression
2 , 8 , 14 , 20
Then, given that,
sum of n terms = 660
The sum of n terms in arithmetic progression is:
Where,
"d" is the common difference between terms
a is the first term of sequence
n is the number of terms
From given,
2 , 8 , 14 , 20
Substituting the terms we get,
Ignore negative value
Thus, n = 15
Thus, sum of first 15 terms will give a sum of 660
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