Question

How many terms of the arithmetic sequence 5, 9, 13,must be added to get 230 ​

Answer 1

Answer:

n=10 pls mark me as the brainliest pls.

Step-by-step explanation:

Answer 2

Concept Introduction:-

It could take the shape of a word or a numerical representation of a quantity's arithmetic value.

Given Information:-

We have been given that the arithmetic sequence $5, 9, 13,$

To Find:-

We have to find that number of  terms of the arithmetic sequence $5, 9, 13,$must be added to get $230$​

Solution:-

According to the problem

$5,9,13 \quad 230$

$a=5, d=9-5=4$, total $n=230$

$\Rightarrow \quad \s_n =n/ 2(2 a+(n-1) d)\\\Rightarrow \quad 230=\frac{n}{2}[2 \times 5+(n-1) 4]\\\Rightarrow 460=n[10+4n-4]\\460=n(6+4n)\\230=n(3+2n)\\\Rightarrow 230=3n+2n^{2}\\\Rightarrow 2n^{2}+3n-230=0$

Solving the equation we get

$n=10$ & $n=-23 / 2$.

Final Answer:-

The correct answer is the value of n is $10$.

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