how many terms of the Gp 3, 3/2 ,3/4 are needed to give the sum 186\32 pls help
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s=a(-r^n +1)/-r+1
186/32=((3)((1/2)^n -1))/(1/2)
((186/32*2)/3)+1=(1/2(^n
186/32=((3)((1/2)^n -1))/(1/2)
((186/32*2)/3)+1=(1/2(^n
tavanya06:
is that the full solution?
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