Question

How many terms of the gp 3,9/2, 27/4,..... Should be taken to get a sum of 1995/32?

Answer 1

Answer:

6

Step-by-step explanation:

Sₙ = a(rⁿ-1)/(r-1)      {a=3, r= 3/2}

1995/32 = 3{(3/2)ⁿ-1} / {(3/2)-1}

1995/(32*2*3) = (3/2)ⁿ-1

729/64 = (3/2)ⁿ

(3/2)⁶=(3/2)ⁿ ===> n=6