Math, asked by shiday19, 8 months ago

How many terms of the sequence -35, -28, -21,..... should be taken so that their sum is zero?

Answers

Answered by mokshitkarra
2

Answer:number of terms to be taken = 11

Step-by-step explanation:

a=-35,d=7 Sn=0,n=?

0=n/2 [2(-35)+(n-1)7]

7n^2-77n=0

n^2 -11n=0

n[n-11]=0

that implies n=11

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