Question

how many terms of the sequence 92, 88, 84.................should be taken to get their sum equal to zero

Answer 1

Step-by-step explanation:

a=92 d=-4

Sn=0

n/2(2a+(n-1)d)=0

If n/2 is zero then n=0

It doesn't satisfy the condition

So, 2a+(n-1)d=0

2a=(1-n)d

2(92)=(1-n)(-4)

2(23)= -(1-n)=n-1

46=(n-1)

n=47

We have to add 47 terms to get the sum as zero