how many terms of the series 1+3+9+....make the sum 364? with steps pls
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133 is the following answer
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Sn=n/2(2a+(n-1)d)
364=n/2(2+(n-1)2)
728=n(2+2n-2)
728=2n^2
n^2=364
n=18
364=n/2(2+(n-1)2)
728=n(2+2n-2)
728=2n^2
n^2=364
n=18
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