how many terms of the series 30, 27, 24 must be taken so that the sum may be 156 solution step by step
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Step-by-step explanation:
a=30
d=-3
we know that
sum=n/2(a+(n-1)d)
156=n/2(30+(n-1)*-3)
156=n/2(33-3n)
312=33n-3n²
n²-11n-104=0
n=(-11+-√(537)/2
=(-11+23)/2
=6
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