How many terms of the series 42,36, 30........amount to 150?
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Answer:
42,36,30....
a=42,d=-6, Sn: 150
sn=n/2{2a+ (n-1)d}
= n/2{2x42+(n-l)-6.}
= n/2{84-6n+6}
= n/2(90-6n)
150 = 45n-3n 2
50=15n-n2
n2-15n+50=0
(n-5)(n-10,)=0
n = 5
5 terms. Ans
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