how many terms of this sequence lies between 100 and 550( sequence= 11, 19,27,35
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Step-by-step explanation:
The A.P is 11,19,27,35....
Here a = 11 , d = t2-t1 = 19-11 =8 , t100 = ?
Therefore, tn =a + ( n-1 ) d
t100 = 11 + ( 100-1 ) 8
t100 = 11 + 99 × 8
t100 = 11 +792
t100 = 803
Now, a=11 , d = t2-t1= 19-11 = 8 , t550 = ?
tn = a + ( n-1 ) d
t550 = 11 + ( 550-1 ) 8
t550 = 11 + 549 × 8
t550 = 11 + 4392
t550 = 4403
Now, t550 - t100
4403 - 803
= 3600
Therefore, 3600 terms of this sequence lies between 100 and 550.
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