Question

how many there digit numbers are divisible by 6 which always leave remainder 1

Answer 1

a=103

d=6

an=997

an=a+(n-1)d

997=103+(n-1)6

997-103=6n-6

894=6n-6

894+6=6n

900=6n

n=900/6

n=150

hence,there are 150 3-digit no. that are divisible by 6 and leave remainder 1....