How many three digit natural numbers are available by 9?
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AP : 108,117,126,............999
a=108;d=9;an=999;n=?
an=a+(n-1)d
999=108+(n-1)(9)
999=108+9n-9
999=99+9n
999-99=9n
900=9n
n=900/9
n=100
Thus 100 three digit no.s are divisible by 9 ...
a=108;d=9;an=999;n=?
an=a+(n-1)d
999=108+(n-1)(9)
999=108+9n-9
999=99+9n
999-99=9n
900=9n
n=900/9
n=100
Thus 100 three digit no.s are divisible by 9 ...
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