How many three digit natural numbers are divisible by5 *
Answers
Therefore, 180 three digit natural numbers are divisible by 5.
Answer:
You Can Write Any 1 Answer Which You Like
Step-by-step explanation:
The first 3-digit natural number which is exactly divisible by 5, is 100, while the last one is 995.
Let A represents the set of 3-digit natural numbers which are exactly divisible by 5, Then
A = {100,105,110,…,985,990,995}
Common difference is 5
Using arithmetic progression method to solve the ptoblem
l = a + ( n - 1)d
where, l is the last term
a is the first time
d is common difference, and
n is number of terms (the variable to be found)
l = 995
a = 100
d = 5
n = ?
995 = 100 + (n - 1)5
995 = 100 + 5n - 5
5n = 900
n = 900/5
n = 180
Therefore, there are 180 three-digit natural numbers which are exactly divisible by 5.
(OR)
We have to form 3 Digit Numbers that are divisible by 5 and we have to select from the digits 0 .. 9 i. e. in all 10 digits.
Now, there are 9 choices for the first digit, since we can’t have 0 as the first digit. There are 10 choices for the 2nd digit and only 2 choices (0 or 5) for the 3rd digit, as the number should be divisible by 5. These are all mutually exclusive choices and thus the answer would be given by
9 * 10 * 2 = 180.
Thus, there are 180 three-digit natural numbers that are divisible by 5.